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Posted on: 09:28:45 AM on October 9, 2014
Find the remainder when 2 to the power of 89 is divided by 89?


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Posted on: 05:15:19 PM on October 8, 2016
When we take successive powers of 2 and find their remainders, we get the following cyclic patterns of cycle length 11. viz 2,4,8,16,32,64,39,78,67,45,1 i.e 211 leaves a remainder 1. Thus 289=(211)8 x 2 leaves a remainder of 2.





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