Question on Limits

Hey Akhil, I think the answer is 1/3

Solution : Multiply both sides by 3, you get (4-1)/ 1.4 + (7-4)/ 4.7 + .................... + (3n+1)-(3n-2)/ (3n-2) (3n+1)

= 1-1/4+1/4-1/7..................+1/( 3n-2 )-1/( 3n+1 )

Solving for n -> infinity gives 1/3

yes the answer is 1/3. u can also do it by normal partial fraction method. 

 write it as  1\3[{4-1}1.4+{7-4.7}+..............{(3n+1)-(3n-2)}\.(3n+1).(3n-2)

finally you will get as n\(3n+1) 

by solving limit answer is 1\3

this can also be solved by expansion through binomial.... its easy once u r used to that processs